1+1/4+1/16+1/32+...+1/2^n
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2\1+4\1+8\1+16\1+32\1?(1-1/2)+(1/2-1/4)+(1/4-1/8)+(1/8-1/16)+(1/16-1/32)=1-1/2+1/2-1/4+1/4-1/8+1/8-1/16+1/16-1/32=1-1/32
1/2+(-1/4)+(-1/8)+(-1/16)+(-1/32)1/2+(-1/4)+(-1/8)+(-1/16)+(-1/32)=1/2-1/4-1/8-1/16-1/32=16/32-8/32-4/32-2/32-1/32=1/321
1/4+1/8+1/16+1/32简便计算原式=1/4+1/8+1/16+1/32+1/32-1/32=1/4+1/8+1/16+1/16-1/32=1/4+1/8+1/8-1/32=1/4+1/4-1/32=1/2-1/32=15/32原
找规律11/41/161/32()()找规律1、1/4、1/16、1/32))找规律填空!@不要妄想记住我1/41/161/321/641/1281/256.1/64.1/128楼主采纳!1/52.1/76
找规律11/41/161/32()()找规律1、1/4、1/16、1/32))找规律填空!@wu蝶恋1/64,1/128
4,2,1,1/2,1/4,()()()1/8,1/32,1/4,1/16()()()1/2,1/6,1/12,1/20,1/30,1/42()()()1、前数为后数的2倍,1/8,1/16,1/322、1/8为1/4的一半,1/32为1/
数学题:巧算巧算:1-(1/4-1/8)-(1/8-1/16)-(1/16-1/32)-(1/32-1/64)怎么巧算啊1-(1/4-1/8)-(1/8-1/16)-(1/16-1/32)-(1/32-1/64)=1-1/4+1/8-1/8
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256令m=1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256两边同时乘2,得:2m=1+1/2+1/4+1/8+...+1/128两式相减,得
1/2-1/4-1/8-16/1-32/1-64/1-128/1-256/1如果题目没有出错的话:1/2-1/4-1/8-16/1-32/1-64/1-128/1-256/1=1/2-(1/2-1/4)-(1/4-1/8)-32-128-2
1/2-1/4-1/8-1/16-1/32-1/64-1/128-1/2561/2-1/4=1/41/4-1/8=1/81/8-1/16=1/161/16-1/32=1/321/32-1/64=1/641/64-1/128=1/1281/1
1/2+1/4+1/8+1/16+1/32+1/64+1/128+.+1/1024很高兴回答你的问题这道题是有技巧的,不是靠死算的下面我给你算一下,希望你能学到其中的技巧1/2+1/4+1/8+1/16+1/32+1/64+1/128+.+
1-2/1-4/1-8/1-16/1-32/1-64/1-128/1应该是1-1/2-1/4-1/8-1/16-1/32-1/64-1/128吧!=1/2-1/4-1/8-1/16-1/32-1/64-1/128=1/4-1/8-1/16-
1-(1/2)-(1/4)-(1/8)-(1/16)-(1/32)-(1/64)-(1/128)-(1/256)简便计算1-(1/2)-(1/4)-(1/8)-(1/16)-(1/32)-(1/64)-(1/128)-(1/256)=1-【
1/2-1/4-1/-1/8-1/16-1/32-1/64----------1/10241/2-1/4=1/4.1/4-1/8=1/8,所以答案=1/10241/2-1/4-1/8.....-1/1024=(512-256-128-64-
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256这个是分母加倍的加法,规律如下1/2=1-1/21/4=1/2-1/41/8=1/4-1/8.1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/
2/1+4/1+4/1+6/1+8/1+16/1+32/1=?1+7÷32=38/32=19/16
简算1/2-(1/2-1/4)-(1/4-1/8)-(1/8-1/16)-(1/16-1/32)-(1/32-1/64)如题~快点哇!九点之前答对的给十点……解1/2-(1/2-1/4)-(1/4-1/8)-(1/8-1/16)-(1/16
计算:1/32+1/64+1/128+2561/2+1/4+1/8+1/16+1/32+1/641/5+1/10+1/20+1/40+1/80+1/1601/3+1/6+1/12+1/24+1/48+1/96除了通分还有简便方法吗?当然有,
1-1/4-1/8-1/16-1/32=17/32怎么算简便计算1-1/4-1/8-1/16-1/32=1-(1/4+1/8+1/16+1/32)=1-(8+4+2+1)/32=1-15/32=17/32=32/32-8/32-4/32-2
128+64+32+16+8+4+2+1+2/1+4/1+8/1+16/1+32/1=?等比数列的前n项和