x2-3x+1=0

x2-3x+1=0x2/(x4-x2+1)请问这是什么啊?希望能把问题完善了好吧?

x2-3x-1=0,求①x21/x2;②x2-1/x2∵x2-3x-1=0∴X-2-1/X=0∴X-1/X=3∴①平方,X²-2+1/X²=9∴X²+1/X²=11②∵(X+1/X)²=X&

已知x2－4x+1=0,求x2／(x2)2－3x2+1x2－4x+1=0两边同除以xx-4+(1/x)=0x+(1/x)=4(x+(1/x))^2=4^2=16x^2+(1/x^2)=16-2=14x2／[(x2)2－3x2+1]=1/[x

已知x2+3x+1=0,求x2+1/X2的值x2指x的平方x^2+3x+1=0方程两边同除以xx+3+1/x=0x+1/x=-3x^2+1/x^2=(x+1/x)^2-2=(-3)^2-2=9-2=7

x2-3x+1=0,求x2+1/x2-2的值x2表示x的平方x^2+1/x^2-2=(x+1/x)^2-4x^2-3x+1=0即x-3+1/x=0所以x+1/x=3(x+1/x)^2-4=5原式值为5

x2-5x+1=0则x2+x2/1你可以参见“韦达定理”方程两个根的积是1,说明他们互为倒数.x^2+1/x^2=(x+1/x)^2-2*x*1/x=（-5）²-2=23

若x2-3x+1=0,求（2x2×x3-5x2×x2+2x3-8x2）÷（x2+1）的值

已知x2-3x+1=0,代数式x2/x4+3x2+1x2-3x+1=0->(x-3/2)平方-5/4=0->x-3/2=正负根号5/2每个结果代入代数式x2/x4+3x2+1就ok

已知x2+3x+1=0,求x2/x4+3x2+1的值1/10x4+3x2+1=x4-x3+(x3+3x2+x)-x+1=x4-x3+x(x2+3x+1)-x+1=x4-x3-x+1=x4-(x3+3x2+x)+3x2+1=x4-x(x2+3

已知x2-3x+1=0,求代数式x2/x4+3x2+1x2-3x+1=0除以x得x-3+1/x=0x+1/x=3(x^4+3x^2+1)/x^2=x^2+3+1/x^2=3+(x+1/x)²-2=1+3²=10∴x2/﹙

已知X2-3X+1=0,求X2/X4+3X2+1的值是多少?∵x²-3x+1=0两边同时除以x得∴x-3+1/x=0∴x+1/x=3x²/(x^4+3x²+1)分子分母同时除以x²得=1/(x

若x2-3x+1=0则x4+x2+1分之x2解x²-3x+1=0两边同时除以x得：x-3+1/x=0即x+1/x=3两边同时平方得：(x+1/x)²=9即x²+2+1/x²=9∴x²+1/x

x2-3x+1=0,则x2/x4+x2+1的值是多少?快,急用x²+1=3x两边平方x^4+2x²+1=4x²两边减去x²x^4+x²+1=3x²所以x²/(x^4+x&

若X2-3X+1=0,求代数式X2/X4+X2+1的值X2-3X+1=0x不等于0时两边同时除以x得x-3+(1/x)=0x+(1/x)=3X2/X4+X2+1=1/[x²+1+(1/x²)]=1/[(x+1/x)

已知x2-3x+1=0,求x2/x4+x2+1的值x2-3x+1=0x+1/x=3平方,得x²+2+1/x²=9x²+1/x²=9-2=7所以x²/(x4+x2+1)=1/(x²+

若X2-3X+1=0,求代数式X2/X4+X2+1的值x^2=3x-1x^2/(x^4+x^2+1)=(3x-1)/[(3x-1)^2+3x]=(3x-1)/[9x^2-6x+1+3x]=(3x-1)/[27x-9-3x+1]=(3x-1)

已知X2-3X-1=0求X2+1/X2的值X2-3X-1=0则X-3-1/X=0则X-1/X=3则(X-1/X)²=3²=9则X²-2+1/X²=9则X²+1/X²=9+2=11

若X2-3X+1=0,求代数式X2/X4+X2+1的值你可以找外教答案为八分之一X2-3X+1=0x不等于0时两边同时除以x得x-3+(1/x)=0x+(1/x)=3X2/X4+X2+1=1/[x²+1+(1/x²)]=

x2+3x+1=0,求x2+1/x2的值.要讲解!x^2+3x+1=0x^2+1=-3x(x^2+1)^2=9x^2x^4+1+2x^2=9x^2x^4+1=7x^2所以x^2+1/x^2=(x^4+1)/x^2=7

如果x2—3x+1=0,求x2+1/x2的值?x^2表示x的平方x^2+1=3x很明显,x不等于0所以x+1/x=3x^2+1/x^2=(x+1/x)^2-2=9-2=7