tanx/x-π.x趋向于π的极限?

tanx/x-π.x趋向于π的极限?

tanx/(x-π) =tan(x-π)/(x-π) =sin(x-π)/(x-π)*1/cos(x-π) 当x→π时,极限sin(x-π)/(x-π)=1 所以原式=1*1/cos0=1