(2X+1)/(x-3)(x+4)=A/(x-3)+B/(x+4) 求A.B的值.
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(2X+1)/(x-3)(x+4)=A/(x-3)+B/(x+4) 求A.B的值.
B(x-3)+A(x+4)=2x+1
B+A=2,4A-3B=1,3B+3A=6,B=A=1
式子可化简得
(2X+1)/(x-3)(x+4)=A/(x-3)+B/(x+4)
=[(A+B)x+4A-3B]/(x-3)(x+4)
所以,
A+B=2
4A-3B=1
解之得
A=1;B=1
a+x/x+1 ,x/x^2-2x-3 ,a/x^2+4x+3
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