∫1/(x^2-3x+2)dx

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∫1/(x^2-3x+2)dx

你好:

∫1/(x^2-3x+2)dx
=∫1/(x-1)*(x-2)dx
=∫1/(x-2)dx -∫1/(x-1)dx
=ln|x-2|-ln|x-1|
=ln|(x-2)/(x-1)|+C


谢谢

∫1/(x^2-3x 2)dx =∫1/(x-1)(x-2)dx=∫(x-1)-(x-2)/(x-1)(x-2)dx=∫1/(x-2)dx-∫1/(x-1)dx=㏑(x-2)/(x-1)+C