已知1/x-1/y=5 求分式-x+xy+y/2x+7xy-2y
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已知1/x-1/y=5 求分式-x+xy+y/2x+7xy-2y
将1/x-1/y=5通分,得y-x/xy=5,
两边同时乘以xy,得y-x=5xy,
带入-x+xy+y/2x+7xy-2y,得5xy+xy/-2*5xy+7xy,
合并同类项,得6xy/-3xy=-2
即,原式等于-2
1/x-1/y=5
所以y-x=5xy
y+xy-x/2x+7xy-2y
=y-x+xy/7xy-2(y-x)
=5xy+xy/7xy-2*5xy
=6xy/-3xy=-2
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