若|2x-y+5|+(x+2y-4)的平方=0,则(2x-y)的三次方-(x-3y)(y-2x)的平方
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若|2x-y+5|+(x+2y-4)的平方=0,则(2x-y)的三次方-(x-3y)(y-2x)的平方
∵|2x-y+5|+(x+2y-4)的平方=0
∴2x-y+5=0,
x+2y-4=0
∴2x-y=-5,
x+2y=4
x-3y=-9
则(2x-y)的三次方-(x-3y)(y-2x)的平方
=(-5)^3-(y-2x)²(x-3y)
=-125-16*(-9)
=19
解决方案:
| X + Y +(2X-Y +5)^ 2 = 0
| X +2 Y | = - (2X-Y +5)^ 2
因为: X +2|≥0,(2X-Y +5)^ 2≥0
所以,为了使X + Y | = - (+5)2X-Y ^ 2建立
必须:
| X +2 Y | = 0 ........................ (1)
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解决方案:
| X + Y +(2X-Y +5)^ 2 = 0
| X +2 Y | = - (2X-Y +5)^ 2
因为: X +2|≥0,(2X-Y +5)^ 2≥0
所以,为了使X + Y | = - (+5)2X-Y ^ 2建立
必须:
| X +2 Y | = 0 ........................ (1)
(2X-Y +5)^ 2 = 0 .................. (2)
(2):2X-Y +5 = 0,即:Y = 2X +5 ............ (3)
代入(1),主要有:X +4 X +10 = 0
:| X +2 | = 0
解决方案是:X = -2 代入(3),有:为y = 2(-2)5 = 1
:= -2,= 1
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